Answer:
The 13.2 meters from that point on the ocean floor to the wreck.
Step-by-step explanation:
As given
A ship's sonar finds that the angle of depression to a ship wrack on the bottom of the ocean is 12.5°.
If a point on the ocean floor is 60 meters.
Now by using the trigonometric identity.
[tex]tan\theta = \frac{Perpendicular}{Base}[/tex]
As shown in the figure given below.
Perpendicular = CB
Base = AC = 60 meters
[tex]\theta = 12.5^{\circ}[/tex]
Put in the identity
[tex]tan\ 12.5^{\circ} = \frac{CB}{AC}[/tex]
[tex]tan\ 12.5^{\circ} = \frac{CB}{60}[/tex]
[tex]tan\ 12.5^{\circ} = 0.22[/tex]
[tex]tan\ 12.5^{\circ} = 0.22[/tex]
[tex]0.22= \frac{CB}{60}[/tex]
CB = 60 × 0.22
CB = 13.2 meters
Therefore the 13.2 meters from that point on the ocean floor to the wreck.
