Answer:
2) ∠SDH and ∠SDT are right angles because SD ⊥ HT.
3) [tex]\bar{SH}\cong \bar{ST}[/tex] as it is given in the question.
4) [tex]\bar{SD}\cong \bar{SD}[/tex] is the reflexive property.
5) ΔSHD ≅ ΔSTD by RHS congruency.
Step-by-step explanation:
Given in the question:
[tex]\bar{SH}\cong \bar{ST}\\\bar{SD}\perp \bar{HT}[/tex]
In ΔSHD and ΔSTD
[tex]\bar{SH}\cong \bar{ST}[/tex] (Given)
[tex]\angle SDH\cong \angle SDT=90^o[/tex] (SD ⊥ HT)
[tex]\bar{SD}\cong \bar{SD}[/tex] (Common)
Therefore, [tex]\Delta SHD\cong \Delta STD[/tex] (By RHS rule)
Reflexive property of congruency is defined as the property in which something is equal to itself. Hence, the reflexive property of these two triangles is [tex]\bar{SD}\cong \bar{SD}[/tex]
