Respuesta :
The temperature of the gas is 183 K
calculation
ideal gas equation = Pv =nRT
where;
P(pressure)= 4.50 atm
V(volume)= 10.0 L
n(number of moles) = 3.00 moles
R( gas constant) = 0.0821 L.atm/mol.K
T(temperature) = ?
make T the formula of the subject by diving both side of equation by nR
T is therefore =Pv/nR
={(4.50 atm x 10.0 l) /(3.00 moles x 0.0821 L.atm/mol.k)} =183 K