Values of R, the ideal gas constant, and the ideal gas equation are given below. Use these to solve the problems. PV = nRT A 10.0-L rigid container holds 3.00 mol H2 gas at a pressure of 4.50 atm. What is the temperature of the gas? (Round to the nearest whole number)

Respuesta :

  The temperature  of the gas   is  183 K

  calculation

  ideal gas equation = Pv =nRT

where;

P(pressure)= 4.50 atm

V(volume)= 10.0 L

n(number of moles) = 3.00 moles

R( gas constant) = 0.0821 L.atm/mol.K

T(temperature) = ?

 make T the formula  of the subject  by  diving both side of equation by nR

T is therefore  =Pv/nR


={(4.50 atm x  10.0 l) /(3.00 moles x 0.0821 L.atm/mol.k)} =183 K


Answer : 183 , 142 , 0.03 , 11.3 And 24.5