Answer:
[tex]\frac{1}{2} QP = UT[/tex]
Step-by-step explanation:
GIVEN : In ΔPQR
S is the mid point of QP
U is the mid point of PR
T is the mid point of QR
Solution :
i) is true i.e [tex]\frac{1}{2} QP = UT[/tex]
Refer the attached file
By mid segment theorem i.e. In a triangle, the line joining the midpoints of any two sides will be parallel to the third side and that same line joining the midpoints is also half of length of third side .
UT is the line joining the two mid points . So, by theorem given above UT is parallel to PQ and 1/2QP=UT.
So, (i) statement is true i.e. [tex]\frac{1}{2} QP = UT[/tex]
Answer:
A) 1/2QP=UT
D) SU II RP
Step-by-step explanation:
A & D ARE THE ANSWERS
