A solution containing 2.8 moles of magnesium bromide is combined with a solution containing excess potassium carbonate. This chemical reaction takes place:
MgBr2(aq) + K2CO3(aq) → MgCO3(s) + 2KBr(aq).

If the volume of the resulting solution is 1.33 liters, what’s the concentration of potassium bromide? Use the periodic table.

A.
0.24 M
B.
2.1 M
C.
3.7 M
D.
4.2 M
E.
5.6 M

Respuesta :

The concentration  of potassium  bromide (KBr)  is  4.2M (answer D)

  calculation

MgBr₂ (aq) +k₂co₃(aq) → MgCO₃(s)  + 2 KBr (aq)

Step  1: use the mole  ratio to determine the  moles of KBr

From equation above  MgBr₂ : KBr  is 1:2  therefore  the moles of KBr  is

=2.8 moles x 2/1 = 5.6 moles

Step 2: find the concentration  of KBr (malarity)

molarity = moles / volume in liters

= 5.6  moles / 1.33 L= 4.2 M ( answer D)


Answer:

Letter D. 4.2 M

Explanation:

I just did it on Edmentum