I'm assuming you want the Thursday excercise solved, since the Wednseday one is not clearly shown.
If this is the case, we can solve the expression as follows: we perform the first division: we have to divide
[tex] 35\div (-5) [/tex]
The result is -7, because a positive divided by a negative is a negative, and 35 divided by 5 is 7.
Next, we have to divide
[tex] (-7)\div(-3) [/tex]
This time, a negative divided by a negative is a positive, so the result is
[tex] \dfrac{7}{3} [/tex]
which has a decimal expansion of
[tex] \dfrac{7}{3} = 2.\bar{3}[/tex]
