Answer:
[tex]A'(0,-2),B'(4,9),C'(-5,3)[/tex]
Step-by-step explanation:
The given triangle ABC has vertices [tex]A(-2,0),B(9,-4),C(3,5)[/tex].
We want to find the coordinates of the image triangle A'B'C' after a counterclockwise rotation through an angle of [tex]90\degree[/tex] about the origin.
The mapping for this transformation is,
[tex]P(x,y)\rightarrow P'(-y,x)[/tex].
This implies that,
[tex]A(-2,0)\rightarrow A'(0,-2)[/tex].
[tex]B(9,-4)\rightarrow B'(4,9)[/tex].
[tex]C(3,5)\rightarrow C'(-5,3)[/tex].
See graph
