Respuesta :
Answer: 0.161 atm
Explanation:
To calculate the partial pressure of helium (He), use the equation PHe = XHe × Ptotal, where XHe is the mole fraction of He, and Ptotal is the total pressure given in the question.
To calculate the mole fraction of helium, we must first calculate the number of moles of helium and hydrogen gas in the mixture.
nHe = 1.00g He/ 4.003 g/mol = 0.2498 mol
nH2 = 1.00g H2 / 2.016 g/mol = 0.4960 mol
ntotal= 0.2498 mol + 0.4960 mol= 0.7458 mol
We can now solve for the partial pressure of helium as follows. Recall that the mole fraction of helium is the ratio of the moles of helium to the total number of moles of gas.
PHe = XHe × Ptotal
= nHe / ntotal × Ptotal
= 90.2498 mol / 0.7458 mol) × 0.480atm
= 0.1608
Therefore, after rounding the answer to two significant figures, we find that the partial pressure of helium gas is about 0.161 atm.
The partial pressure of helium (He) in the mixture containing 1 g of H₂ and 1 g of He is 0.16 atm
We'll begin by calculating the number of mole of each gas present in the mixture.
For H₂:
Mass of H₂ = 1 g
Molar mass of H₂ = 2 × 1 = 2 g/mol
Mole of H₂ =?
Mole = mass / molar mass
Mole of H₂ = 1/2
Mole of H₂ = 0.5 mole
For He:
Mass of He = 1 g
Molar mass of He = 4 g/mol
Mole of He =?
Mole = mass / molar mass
Mole of He = 1/4
Mole of He = 0.25 mole
Next, we shall determine the total mole.
Mole of H₂ = 0.5 mole
Mole of He = 0.25 mole
Total mole =?
Total mole = 0.5 + 0.25
Total mole = 0.75 mole
Next, we shall determine the mole fraction of He.
Mole of He = 0.25 mole
Total mole = 0.75 mole
Mole fraction of He =.?
Mole fraction = mole / total mole
Mole fraction of He = 0.25 / 0.75
Mole fraction of He = 0.33
Finally, we shall determine the partial pressure of He.
Mole fraction of He = 0.33
Total pressure = 0.48 atm
Partial pressure of He =?
Partial pressure = mole fraction × total pressure
Partial pressure of He = 0.33 × 0.48
Partial pressure of He = 0.16 atm
Therefore, the partial pressure of helium (He) in the mixture is 0.16 atm
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