5x+7y=41
3x-2y=6
Multiply each equation by coefficient to y
2(5x+7y)=2(41 )
7(3x-2y)=7(6 )
Add both equations
10x+14y=82
+ 21x-14y=42
____________
3x = 124
Divide both sides by 3 to find x
3x/3=124/3
X= 4
Now select an equation substitute x to solve for y .
10x+14y=82
10(4)+14y=82
40+14y= 82
Subtract 40 both sides
40-40+14y=82-40
14y= 42
Divide 14 both sides
14y/14=42/14
Y= 3
Your answer is point form ( 4,3)