Respuesta :

[tex]\bf 2~~,~~\stackrel{2+8}{10}~~,~~\stackrel{10+8}{18}~\hspace{7em}\stackrel{\textit{so the common difference is}}{d=8} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=2\\ d=8\\ n=24 \end{cases} \\\\\\ a_{24}=2+(24-1)8\implies a_{24}=2+(23)8 \\\\\\ a_{24}=2+184\implies a_{24}=186[/tex]