Given : [tex]\frac{1}{9\sqrt{3}}[/tex]
[tex]\implies \frac{1}{3^2\times3^\frac{1}{2}} = \frac{1}{3^(^2^+^\frac{1}{2}^)} = \frac{1}{3^(^\frac{5}{2}^)} = 3^(^\frac{-5}{2}^)[/tex]
