What is the midpoint of line segment AB?
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Answer
Midpoint = (3, 5.5)
Step by step explanation
Here we have to use the midpoint formula.
Midpoint = ( [tex]\frac{x1 + x2}{2} , \frac{y1 + y2}{2} \\[/tex])
Here the point A = (-1, 8) and B = (7, 3)
x1 = -1, y1 = 8, x2 = 7 and y2 = 3
Now plug in these values into the formula.
Midpoint = ([tex]\frac{-1 + 7}{2} , \frac{8 + 3}{2}[/tex]
= (6/2, 11/2)
= (3, 5.5)
Therefore, the midpoint the line segment AB is (3, 5.5)
Thank you.
Answer:
(3, 5.5)
Step-by-step explanation:
We are given a line segment AB and the coordinates of two points: A(-1, 8) and B(7, 3) and we are to find the mid-point of line segment AB.
We know that,
mid-point = [tex](\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )[/tex]
so putting in the values of the given coordinates to get:
Mid-point of AB = [tex](\frac{-1+7}{2} ,\frac{8+3}{2} )[/tex]
[tex]=(\frac{6}{2} ,\frac{11}{2} )[/tex]
[tex]=(3, 5.5)[/tex]
Therefore, the mid point the line segment AB is (3, 5.5).