Answer:
The correct answer is option A.
Step-by-step explanation:
For the given triangles to be similar the segment AD must be an altitude of ΔABC.
We can provide a theorem for the same:
If we draw an altitude from the right angle of any right triangle, then the two triangles formed are similar to the original triangle.
Also all the three triangles are similar to each other.
Like here, in the triangle ABC, we draw an altitude from A to the side BC, thus forming 2 triangles; ΔDBA and ΔDAC. These both will be similar to ΔABC.
So, by the theorem it is proven that ΔABC is similar to ΔDBA.
Therefore, option A is correct.