Respuesta :
When object falls freely we can say
its initial speed will be ZERO
and its acceleration due to gravity must be
[tex]a = g = 9.8 m/s^2[/tex]
Now we need to find the distance of free fall in 3 s of time
So here we will use kinematics
[tex]y = v* t + \frac{1}{2} at^2[/tex]
now we will plug in all values in it
[tex]y = 0 + \frac{1}{2}* 9.8 * 3^2[/tex]
[tex]y = 44.1 m[/tex]
So it will fall by total distance of 44.1 m
Answer:
The brick will cover a distance of [tex]44.1\;\rm{m[/tex].
Explanation:
Given: A brick starting from rest fall freely in 3 seconds.
As mentioned in question,
When an object falls freely then its initial speed will be [tex](u)=0\; \rm{m/s[/tex].
Acceleration due to gravity is [tex]a=g=9.8\;\rm{m/s^{-2[/tex].
Time [tex](t)=3\; \rm{seconds[/tex]
Using the laws of motion: [tex]s=ut+\frac{1}{2}at^2[/tex]
Substiuting all the values we get:
[tex]s=0\times3+\frac{1}{2}\times9.8\times3^2\\s=0.5\times9.8\times 9\\s=44.1\;\rm{m[/tex]
Therefore, the brick will cover a distance of [tex]44.1\;\rm{m[/tex].
Learn more about laws of motion here:
https://brainly.com/question/17338790?referrer=searchResults
