Respuesta :
Jennifer used : 2/7.
Remaining length of the ribbon = 10/21.
Total length of the ribbon in starting = Length of used ribbon + Remaining length of the ribbon .
Therefore,
Total length of the ribbon in starting = 2/7 +10/21
[tex]\frac{2}{7}+\frac{10}{21}[/tex]
[tex]\mathrm{Least\:Common\:Multiplier\:of\:}7,\:21:\quad 21[/tex]
[tex]\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}[/tex]
[tex]\frac{2}{7}=\frac{2\cdot \:3}{7\cdot \:3}=\frac{6}{21}[/tex]
[tex]=\frac{6}{21}+\frac{10}{21}[/tex]
[tex]=\frac{16}{21}[/tex]
Therefore, Jennifer start with 16/21 meter of ribbon.
Answer with explanation:
Amount of Ribbon used by Jennifer to make bows for the her cousins [tex]=\frac{2}{7}[/tex] of meter
Amount of Ribbon Left [tex]=\frac{10}{21}[/tex]
Let Total amount of Ribbon Possessed by Jennifer = x meter
Writing the above statement in terms of equation
[tex]\frac{2x}{7}+\frac{10}{21}=x\\\\x-\frac{2x}{7}=\frac{10}{21}\\\\\frac{5x}{7}=\frac{10}{21}\\\\ x=\frac{10 \times 7}{5 \times 21}\\\\ x=\frac{2}{3}[/tex]
Total Ribbon Possessed by [tex]=\frac{2}{3}[/tex] meter
