Answer:
The answer is 8.
Step-by-step explanation:
If is
[tex]\sqrt{r^{64}}=\sqrt{r^{32\cdot2}}=\sqrt{(r^{32})^2}=r^{32}[/tex]
Used:
[tex](a^n)^m=a^{nm}\\\\\sqrt{a^2}=a\ for\ a\geq0[/tex]
[tex]\sqrt{64}=8[/tex] because [tex]8^2=64[/tex]
