Answer:
Energy in KWH = Power in KW * Time in hours
Cost is # of KWH * the cost per KWH
350 kwh
Explanation:
The monthly cost of using a 700-W refrigerator that runs for 10 h a day if the cost per kWh is $0.20 is $42.
The cost price per watt is the amount of money required to use one watt or kilo watt electricity,
To find the total cost of electricity used, multiply the cost price of electricity per watt to total watts of electricity used.
Given information-
The power used by the refrigerator is 700- W per hour.
Total run time of the refrigerator is 10 hours per day.
The cost of the electricity is $0.20 kWh.
As, the power used by the refrigerator is 700- W per hour and total run time of the refrigerator is 10 hours per day. The power used by the refrigerator per day is,
[tex]P=700\times10\\P=7000\rm Wh\\P=7\rm kWh[/tex]
There is total 30 days in a month. Thus the total power used by the refrigerator per month is,
[tex]P=7\times30\\P=210\rm kWh[/tex]
As the cost of the electricity is $0.20 kWh. Thus the cost of 210 kWh electricity is,
[tex]C=0.2\times210\\C=42[/tex]
Thus the monthly cost of using a 700-W refrigerator that runs for 10 h a day if the cost per kWh is $0.20 is $42.
Learn more about the cost price per watt here;
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