Respuesta :

Hello!

Answer:-3


Step-by-step explanation:

First, convert mixed numbers to improper fractions.

[tex]-5 \frac{1}{3}-(-2\frac{1}{3})[/tex]

[tex]5\frac{1}{3}=\frac{5*3+1}{3}=\frac{16}{3}[/tex]

[tex]-\frac{16}{3}-(-2*\frac{1}{3})[/tex]

[tex]=-\frac{16}{3}-(-2\frac{1}{3})[/tex]

Again, convert mixed numbers to improper fractions.

[tex]-\frac{16}{3}-(-2\frac{1}{3})[/tex]

[tex]2\frac{1}{3}=\frac{2*3+1}{3}=\frac{7}{3}[/tex]

[tex]-\frac{16}{3}-(-\frac{7}{3})[/tex]

Next, apply rule.

[tex]-\frac{16}{3}+\frac{7}{3}[/tex]

Since the denominators are equal, combine the fractions.

[tex]\frac{-16+7}{3}[/tex]

Then, add and subtract by the numbers.

[tex]-16+7=-9[/tex]

[tex]=\frac{-9}{3}[/tex]

Apply the fraction rule.

[tex]-\frac{9}{3}[/tex]

Finally, divide into the numbers.

[tex]\frac{9}{3}=3[/tex]

[tex]=-3[/tex]

Hope this helps!

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-Charlie