Respuesta :
Given
velocityΔ v₁ = 6m/s
v₂ = 11m/s
Δ time = Δ t = 2s
sign / indicate as division.
acceleration a = Δv/ Δt
a = (v₂-v₁) / Δt
a = (11m/s -6m/s ) / 2s
a = (5m/s) / 2s
accerelation a = 2.5m
Given
velocityΔ v₁ = 6m/s
v₂ = 11m/s
Δ time = Δ t = 2s
sign / indicate as division.
acceleration a = Δv/ Δt
a = (v₂-v₁) / Δt
a = (11m/s -6m/s ) / 2s
a = (5m/s) / 2s
accerelation a = 2.5m