[tex]Solution, -x-2>2\left(3-x\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>8\:\\ \:\mathrm{Interval\:Notation:}&\:\left(8,\:\infty \:\right)\end{bmatrix}[/tex]
[tex]Steps:[/tex]
[tex]\mathrm{Expand\:}2\left(3-x\right):\quad 6-2x, -x-2>6-2x[/tex]
[tex]\mathrm{Add\:}2\mathrm{\:to\:both\:sides}, -x-2+2>6-2x+2[/tex]
[tex]\mathrm{Simplify}, -x>-2x+8[/tex]
[tex]\mathrm{Add\:}2x\mathrm{\:to\:both\:sides},-x+2x>-2x+8+2x[/tex]
[tex]\mathrm{Simplify}, x>8[/tex]
The correct answer is x>8
Hope This Helps!!!
