The magnitude of electrical force between them is about 7.52 × 10⁻¹¹ Newton
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Further explanation
Electric charge consists of two types i.e. positively electric charge and negatively electric charge.
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There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :
[tex]\large {\boxed {F = k \frac{Q_1Q_2}{R^2} } }[/tex]
F = electric force (N)
k = electric constant (N m² / C²)
q = electric charge (C)
r = distance between charges (m)
The value of k in a vacuum = 9 x 10⁹ (N m² / C²)
Let's tackle the problem now !
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Given:
charge of proton = q₁ = 1.6 × 10⁻¹⁹ C
charge of electron = q₂ = 1.6 × 10⁻¹⁹ C
distance between proton and electron = R = 1.75 nm = 1.75 × 10⁻⁹ m
Unknown:
electrical force between them = F = ?
Solution:
[tex]F = k \frac{q_1 q_2}{R^2}[/tex]
[tex]F = 9 \times 10^9 \times \frac{ 1.6 \times 10^{-19} \times 1.6 \times 10^{-19} }{ ( 1.75 \times 10^{-9} )^2 }[/tex]
[tex]F = 9 \times 10^9 \times \frac{ 2.56 \times 10^{-38} }{ 3.0625 \times 10^{-18} }[/tex]
[tex]F \approx 7.52 \times 10^{-11} \texttt { Newton}[/tex]
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Learn more
- The three resistors : https://brainly.com/question/9503202
- A series circuit : https://brainly.com/question/1518810
- Compare and contrast a series and parallel circuit : https://brainly.com/question/539204
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Answer details
Grade: High School
Subject: Physics
Chapter: Static Electricity
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Keywords: Series , Parallel , Measurement , Absolute , Error , Combination , Resistor , Resistance , Ohm , Charge , Small , Forces
