A spring with a pointer attached is hanging next to a scale marked in millimeters. Three different packages are hung from the spring, in turn, as shown in the figure. (a) Which mark on the scale will the pointer indicate when no package is hung from the spring? (b) What is the weight W of the third package?

Respuesta :

solution;

[tex]the expression for force applied on the spring due to the load is\\

f=k\Delta x\\

here,\Delta x is the extension in the spring due to appling force\\

given three case as following\\

110N=k(40-x_{o})----------1\\

240N=k(60-x_{o})----------2\\

w=k(30-x_{o})-------------3\\[/tex][tex]To calculate the accrual length of the spring,solve th equation 1 and 2\\

\frac{110N}{240N}=\frac{k(40-x_{o})}{k(60-x_{o})}\\

0.458=\frac{k(40-x_{o})}{k(60-x_{o})}\\

0.458(60mm-x_{o})=(40mm-x_{o})\\

x_{o}(1-0.458)=(40-60(0.458))mm\\

x_{o}\frac{12.52}{0.542}\\

=23.1mm\\

to calculate the force on the spring in case,\\

solve the equation 1 and 2\\

\frac{110}{w}=\frac{k(40-x_{o})}{k(60-x_{o})}\\

\frac{110}{w}=\frac{(40mm-23.1mm)}{30mm-23.1mm}\\

w=\frac{110}{2.45}=44.9N[/tex]