The original price for one lunch special is $19.
Explanation
The original price for one lunch special is 'p' dollar.
He wins a coupon for $4 off for each of five days. That means , he needs to pay [tex](p-4)[/tex] dollar each day.
So, the total amount needed to pay for 5 days [tex]= 5(p-4)[/tex] dollar
Given that, he pays $75 for his 5 lunch specials. So the equation will be.....
[tex]5(p-4)= 75\\ \\ 5p-20=75\\ \\ 5p= 75+20\\ \\ 5p= 95\\ \\ p=\frac{95}{5}=19[/tex]
So, the original price for one lunch special is $19.
