acceleration of car is 1.8 m/s^2
time = 14 s
initial speed = 14 m/s
so the final speed is calculated by
[tex]v_f = v_i + at[/tex]
[tex]v_f = 14 + 14 * 1.8[/tex]
[tex]v_f = 39.2 m/s[/tex]
so the total distance moved in this interval of time is
[tex]d = \frac{v_f + v_i}{2}* t[/tex]
[tex]d = \frac{39.2 + 14}{2}* 14[/tex]
[tex]d = 372.4 m[/tex]
now the average speed is given as
[tex]v = \frac{d}{t}[/tex]
[tex]v = \frac{372.4}{14}[/tex]
[tex]v = 26.6 m/s[/tex]
so the average speed will be 26.6 m/s