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Solid potassium fluoride decomposes into fluorine gas and solid potassium .
Write a balanced chemical equation for this reaction.

Respuesta :

transitionstate

Answer:

                2 KF ₍s₎    →    F₂ ₍g₎  +  2 K ₍s₎

Explanation:

                    Chemical Formula of Potassium Fluoride  =  KF

                    Chemical Formula of Fluorine Gas  =  F₂

                    Chemical Formula of Solid Potassium  =  K

Step 1: Write the unbalance chemical equation,

                                             KF    →    F₂  +  K

Step 2: Balance Fluorine Atoms;

As there is one fluorine atom on left hand side and two fluorine atoms on right hand site therefore, to balance them multiply KF on left hand side by 2 i.e.

                                            2 KF    →    F₂  +  K

Step 3: Balance Potassium Atoms;

As there are two potassium atoms on left hand side and one potassium atom on right hand site therefore, to balance them multiply K on right hand side by 2 i.e.

                                             2 KF    →    F₂  +  2 K

Step 4: Assign Physical states as,

                                      2 KF ₍s₎    →    F₂ ₍g₎  +  2 K ₍s₎

Balanced chemical equation is defined as the number of atoms present in each element is equal on the reactant and product sides. The equation stands true, if the reaction follows the law of conservation of mass. The balanced chemical equation for fluorine gas and potassium is:

  • [tex]2\text{KF}_{\text (s)} \;\rightarrow\; \text{F}_{2}_{\text (g)} + 2 \text {K}_{\text (s)}[/tex]

The balanced chemical equation when potassium fluoride decomposes into fluorine gas and solid potassium can be represented as:

  • Chemical formula of Potassium Fluoride - KF
  • Chemical Formula of Fluorine gas - F[tex]_{2}[/tex]
  • Chemical Formula of Solid Potassium - K

The equation can be written as:

[tex]{\text{KF}_{\text (s)} \;\rightarrow\; \text{F}_{2}_{\text (g)} + {\text K}_{\text (s)}[/tex]

In the equation, there are two atoms of fluorine gas on the product's side, whereas, on the reactant side, it is only one. Balancing fluoride atoms, equation becomes:

[tex]{\text{2 KF}_{\text (s)} \;\rightarrow\; \text{F}_{2}_{\text (g)} + \text {K}_{\text (s)}[/tex]

Now, the potassium on the reactant side is two, whereas on the product's side it is only one. Balancing potassium ions, we get:

[tex]{\text{2 KF}_{\text (s)} \;\rightarrow\; \text{F}_{2}_{\text (g)} + \text {2 K}_{\text (s)}[/tex]

Therefore, the balanced equation of potassium fluoride when decomposes into fluoride gas and solid potassium, it becomes:

[tex]{\text{2 KF}_{\text (s)} \;\rightarrow\; \text{F}_{2}_{\text (g)} + \text {2 K}_{\text (s)}[/tex]

To know more about balanced chemical equations, refer to the following link:

https://brainly.com/question/11532459?referrer=searchResults