A train slows down as it rounds a sharp horizontal turn, going from 92.0 km/h to 54.0 km/h in the 16.0 s that it takes to round the bend. The radius of the curve is 130 m. Compute the acceleration at the moment the train speed reaches 54.0 km/h. Assume the train continues to slow down at this time at the same rate.

Respuesta :

Calculation of centripetal acceleration(ac):

[tex]a_c=\frac{v^2}{r}[/tex]

we can change our speed in terms of m/s

[tex]v=54km/h=54*\frac{1000}{3600} m/s[/tex]

now, we can plug these values

[tex]a_c=\frac{(54*\frac{1000}{3600})^2}{130}[/tex]

[tex]a_c=1.73077m/s^2[/tex]

Calculation of tangential acceleration(at):

[tex]a_t=\frac{\Delta v}{\Delta t}[/tex]

now, we can plug values

[tex]a_t=\frac{(54-92)*\frac{1000}{3600} }{16}[/tex]

now, we can simplify it

[tex]a_t=-0.65972 m/s^2[/tex]

Calculation of resultant acceleration:

[tex]a=\sqrt{(a_c)^2+(a_t)^2}[/tex]

now, we can plug values

[tex]a=\sqrt{(1.73077)^2+(-0.65972)^2}[/tex]

[tex]a=1.85224m/s^2[/tex].............Answer