Mole = 0.055 mol
Step 1: Calculate Mass of Glucose in 200 mL solution:
As,
100 mL Solution contains = 5 g of Glucose
So,
200 mL Solution will contain = X g of Glucose
Solving for X,
X = (200 mL × 5 g) ÷ 100 mL
X = 10 g of Glucose
Step 2: Calculate Moles for 10 g of Glucose:
As,
Mole = Mass ÷ M.Mass
M.Mass of Glucose = 180 g.mol⁻¹
So,
Mole = 10 g ÷ 180 g.mol⁻¹
Mole = 0.055 mol
The number of moles that are in 200 milliliters of the glucose solution is 0.0556 mole
From the question,
We are to determine the number of moles there are in 200 milliliters of the glucose solution.
First, we will determine the mass of glucose in this solution.
From the given information,
We have that
A solution contains 5 grams of glucose per 100 milliliters
Now,
If the solution contains 5 grams of glucose per 100 milliliters
Then,
The solution will contain 2 × 5 grams of glucose in the 200 milliliters solution
2 × 5 = 10
∴ 10 grams of glucose are in the 200 milliliters solution
Now, for the number of moles in the 200 milliliters solution
Let number of moles present be x
From the given information,
We have that
Each mole of glucose weighs 180 grams
Now,
If 1 mole of glucose weight 180 grams
Then,
x mole of glucose will weigh 10 grams
x = [tex]\frac{10 \times 1}{180}[/tex]
x = [tex]\frac{1}{18}[/tex]
x = 0.0556 mole
Hence, the number of moles that are in 200 milliliters of the glucose solution is 0.0556 mole.
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