Write the ratios for sin A and cos A
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[tex]sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}[/tex]
[tex]\sin A=\dfrac{3}{5},\ \cos A=\dfrac{4}{5}[/tex]
Trigonometry ratios are used to represent lengths of a right-angled triangle.
The ratios for sin A and cos A are 3/5 and 4/5
Sine ratio is calculated as:
[tex]\mathbf{Sin = \frac{Opposite}{Hypotenuse}}[/tex]
So, we have:
[tex]\mathbf{sin\ A = \frac{3}{5}}[/tex]
Cosine ratio is calculated as:
[tex]\mathbf{Cos= \frac{Adjacent}{Hypotenuse}}[/tex]
So, we have:
[tex]\mathbf{cos\ A= \frac{4}{5}}[/tex]
Hence, the ratios for sin A and cos A are 3/5 and 4/5
Read more about trigonometry ratios at:
https://brainly.com/question/24888715