Respuesta :
Answer:- C = 3.024 g, H = 0.42 g, N = 1.176 g and O = 4.032 g
Solution:- The compound contains C, H, N and O. On combustion, all the carbon is converted to carbon dioxide, All hydrogen is converted to water and all the nitrogen is converted to nitrogen dioxide.
From the grams of all these, we could calculate their moles and then using mol ratio of these products and the number of moles of C, H and N present in them, we calculate the moles of C, H and N respectively. Further, these moles are converted to grams. On subtracting the sum of grams of C, H and N from the mass of the sample, the mass of oxygen is calculated.
The calculations are as follows:
Calculations for the grams of C:-
[tex]11.088gCO_2(\frac{1molCO_2}{44gCO_2})(\frac{1molC}{1molCO_2})(\frac{12gC}{1molC})[/tex]
= 3.024 g C
Calculations for the grams of H:-
[tex]3.780gH_2O(\frac{1molH_2O}{18gH_2O})(\frac{2molH}{1molH_2O})(\frac{1gH}{1molH})[/tex]
= 0.42 g H
Calculations for the grams of N:-
[tex]3.864gNO_2(\frac{1molNO_2}{46gNO_2})(\frac{1molN}{1molNO_2})(\frac{14gN}{1molN})[/tex]
= 1.176 g N
Mass of the compound is given as 8.652 g. Now we could calculate the grams of oxygen as:
mass of oxygen = 8.652 - (3.024 + 0.42 + 1.176)
= 8.652 - 4.62
= 4.032 g
So, 8.652 grams of the compound contains 3.024 g of C, 0.42 g of H, 1.176 g of N and 4.032 g of O.
