Respuesta :
We use the relation between frequency, speed and wavelength as
[tex]\lambda = \frac{f}{v}[/tex].
Here, [tex]\lambda[/tex] is wavelength , f is frequency and v is speed.
Given [tex]f = 2.8 \ MHz[/tex] and we take the speed of sound in aluminium,[tex]v = 5100 \ m/s[/tex].
Substituting these values in above relation, we get
[tex]\lambda = \frac{5100 \ m/s}{2.8 \ MHz } = \frac{5100 \ m/s}{ 2.8 \times 10 ^6 Hz} = 1821.43 \times 10^{-6} m[/tex]
Thus , the wavelength of given ultrasound wave traveling through aluminum is [tex]1821.43 \times 10^{-6} \ m = 0.001821 \ m = 1.82 \ mm[/tex]
