a) For the motion of car with uniform velocity we have , [tex]s = ut+\frac{1}{2}at^2[/tex], where s is the displacement, u is the initial velocity, t is the time taken a is the acceleration.
In this case s = 520 m, t = 223 seconds, a =0 [tex]m/s^2[/tex]
Substituting
[tex]520 = u*223\\ \\u = 2.33 m/s[/tex]
The constant velocity of car a = 2.33 m/s
b) We have [tex]s = ut+\frac{1}{2} at^2[/tex]
s = 520 m, t = 223 seconds, u =0 m/s
Substituting
[tex]520 = 0*223+\frac{1}{2} *a*223^2\\ \\ a = 0.0209 m/s^2[/tex]
Now we have v = u+at, where v is the final velocity
Substituting
v = 0+0.0209*223 = 4.66 m/s
So final velocity of car b = 4.66 m/s
c) Acceleration = 0.0209 [tex]m/s^2[/tex]
