A baseball player hit 62 home runs in a season. Of the 62 home​ runs, 24 went to right​ field, 17 went to right center​ field, 9 went to center​ field, 10 went to left center​ field, and 2 went to left field.

​(a)
What is the probability that a randomly selected home run was hit to right​ field?
​(b)
What is the probability that a randomly selected home run was hit to left​ field?
​(c)
Was it unusual for this player to hit a home run to left​ field? Explain.

Respuesta :

Explanation

Total home runs = 62

Right field = 24 ,  Right center field = 17,  Center field = 9 ,  Left center field = 10 and Left field = 2

(a) The probability that a randomly selected home run was hit to right​ field            = (Number of right field / Total home runs) = [tex]\frac{24}{62} = 0.3870...[/tex]

(b) The probability that a randomly selected home run was hit to left​ field       =  (Number of left field / Total home runs) = [tex]\frac{2}{62}= 0.0322...[/tex]

(c)  As the probability that a home run was hit to the left field is 0.0322... or 3.22...% , that means there is very low chance for hitting to the left field. So, it was unusual for this player to hit a home run to left​ field.