Respuesta :
[tex]\bf 1~~,~~\stackrel{-\frac{2}{3}\cdot 1}{-\frac{2}{3}}~~,~~\stackrel{-\frac{2}{3}\cdot -\frac{2}{3}}{\frac{4}{9}}~~,....[/tex]
so, as we can see, it's really multiplying the previous term by -2/3, to get the next term, namely, -2/3 is the common ratio, and of course, the first term is 1.
[tex]\bf n^{th}\textit{ term of a geometric sequence} \\\\ a_n=a_1\cdot r^{n-1}\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\[-0.5em] \hrulefill\\ a_1=1\\ r=-\frac{2}{3} \end{cases} \\\\\\ a_n=1\left( -\frac{2}{3} \right)^{n-1}\implies a_n=\left( -\frac{2}{3} \right)^{n-1}[/tex]
Answer:
The answer is A, the answer to the second part is C
Step-by-step explanation:
:D
