Graph:
x - y^2 = 6
Solution:
Parabola with Vertex at ( h, k ) = ( 6, 0 ), and Focal Length | p | = 1 / 4
Steps:
x - y^2 = 6
Parabola standard equation:
4p ( x - h ) = ( y - k )^2 is the standard equation for a right - Left facing parabola with vertex at ( h, k ) and a focal length of | p |
Rewrite:
x - y^2 = 6
Standard Form:
4 * 1 / 4 ( x - 6 ) = ( y - 0 )^2
Therefore, Parabola properties are:
( h, k ) = ( 6, 0 ), p = 1 / 4
Hope that helps!!!! : )
