Respuesta :
So for this, I will be making the equation using the slope-intercept form, which is y=mx+b (m = slope, b = y-intercept).
Since we have the slope, 1/2, we can just plug in (2,-3) into the equation and solve for b as such:
[tex] -3=\frac{1}{2}*2+b\\ -3=1+b\\ -4=b [/tex]
Putting everything together, our equation is y = 1/2x - 4.
The equation of a line that has a slope of 1/2 and passes through point (2, -3) is 2y - x = -8
The standard equation of a line in slope-intercept form is expressed as:
y = mx + b where:
- m is the slope
- (x0, y0) is the point on the line
Given the following:
Slope = 1/2
(x0, y0) = (2, -3)
Substitute the given parameters into the formula above:
[tex]y - (-3) = 1/2(x-2)\\y + 3 = 1/2(x-2)\\2(y +3) = x - 2\\2y + 6 = x - 2\\2y -x = -2-6\\2y - x = -8\\[/tex]
Hene the equation of a line that has a slope of 1/2 and passes through point (2, -3) is 2y - x = -8
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