Respuesta :
I hope you meant, a cross between BbPp and BbPp, else for bbpp x bbpp, all the progeny will be bbpp.
We need to work out a Punnett square to determine the genotypes resulting from the cross between BbPp and BbPp. The dyhybrid cross results in 16 different genotypes, of which a few have the same phenotypes.
It can be seen that there are 4 different kinds of phenotypes present, in the ratio 9:3:3:1.
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We assume that these genes assort independently, have no interaction between them, and express complete dominance. By crossing two dihybrid individuals, it is expected a phenotypic ratio of 9:3:3:1 of the progeny.
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Available data:
Two diallelic genes involved in hair color and horns development
Gene for Hair color
- B is the dominant allele and codes for black
- b is the recessive allele and codes for red
Gene for horns development
- P is the dominant allele and codes for polled or lacking horns
- p is the recessive allele and codes for horns
We will assume that these genes assort independently and express complete dominance.
Cross: bbpp × bbpp
F1) 100% bbpp ⇒ red haired animals with horns
We will perform another cross, just in case, for you to know how to proceed in the presence of dominant and recessive alleles.
Cross: Between two dihybrid individuals
Parentals) BbPp x BbPp
Gametes) BP, Bp, bP, bp
BP, Bp, bP, bp
Punnett square) BP Bp bP bp
BP BBPP BBPp BbPP BbPp
Bp BBPp BBpp BbPp Bbpp
bP BbPP BbPp bbPP bbPp
bp BbPp Bbpp bbPp bbpp
F1) Genotypes
- BBPP ⇒ 1/16
- BBPp ⇒ 2/16
- BbPP ⇒ 2/16
- BBpp ⇒ 1/16
- BbPp ⇒ 4/16
- Bbpp ⇒ 2/16
- bbPP ⇒ 1/16
- bbPp ⇒ 2/16
- bbpp ⇒ 1/16
Phenotypes
- 9/16 ⇒ B-P- ⇒ Black-haired with polled or lacking horns
- 3/16 ⇒ B-pp ⇒ Black-haired with horns
- 3/16 ⇒ bbP- ⇒ Red-haired with polled or lacking horns
- 1/16 ⇒ bbpp ⇒ Red-haired with horns
Note: The symbol - represents either a dominant or a recessive allele.
So, according to this last cross, the expected phenotypic ratio of the offspring is 9:3:3:1.
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