Answer: [tex]243\times 10^{-23}[/tex] grams
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles. and weighs equal to the molecular mass.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given atoms}}{\text {Avogadro's number}}=\frac{6}{6.023\times 10^{23}}=1.0\times 10^{-23}moles[/tex]
1 mole of Americium weighs = 243 g
Thus [tex]1.0\times 10^{-23}moles[/tex] of Americium weigh=[tex]\frac{243}{1}\times 1.0\times 10^{-23}=243\times 10^{-23}g[/tex]
Thus the mass mass in grams of a sample of Americium containing six atoms is [tex]243\times 10^{-23}[/tex]
