I'm assuming the die is 6 sided. The number of leaves required to show the outcome would be the number of ways you can get any number on the die times the number of ways you can pick a number on the spinner. That would be 6*8=48. I'm also assuming you're talking about the final outcome because the answer varies on whether you start with spinning the spinner or rolling the die.
The number of leaves on a tree diagram needed to represent all possible combinations of rolling a die and spinning a spinner with 8 sections is 48.
An event is a specified set of results of a random experiment in probability theory. Because the sample space is the collection of all potential outcomes of a random experiment, another definition of an event is any subset of a sample space.
The number of leaves on a tree diagram represents the number of possible outcomes that the events can produce.
Since a dice has 6 faces, therefore, 6 outcomes are possible of rolling a dice. Also, the number of outcomes that the spinner can produce with 8 sections is 8.
Now, the total number of outcomes that are possible for the two happening simultaneously is,
Number of possible outcomes
= Number of outcomes from dice × Number of outcomes from spinner
= 6 × 8
= 48
Hence, the number of leaves on a tree diagram needed to represent all possible combinations of rolling a die and spinning a spinner with 8 sections is 48.
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