Find the quotient of the quantity negative 36 times x to the 3rd power minus 6 times x to the 2nd power plus 12 times x all over negative 6 times x. −36x3 − 6x2 − 2 −6x2 + x − 2 6x2 − x + 2 6x2 + x − 2

Respuesta :

You can pick the correct answer choice just by looking at the term with the highest degree.

... (36x³)/(-6x) = (-36/6)·(x³/x) = -6x²

The best choice is the second one:

... −6x² + x − 2

Answer:

[tex]-6x^2+x-2[/tex]

Step-by-step explanation:

[tex]\frac{36x^3-6x^2+12x}{-6x}[/tex]

To divide this,we divide each term by [tex]-6x[/tex]

Apply exponential property

[tex]\frac{a^m}{^n}=a^{m-n}[/tex]

[tex]\frac{36x^3}{-6x} =-6x^2[/tex]

[tex]\frac{-6x^2}{-6x} =x[/tex]

[tex]\frac{12x}{-6x} =-2[/tex]

So the simplified expression is

[tex]-6x^2+x-2[/tex]