Respuesta :

PenguinHelper
The zeroes of this function are x = 2, 4.

We can find this by factoring. Factoring x²-6x+8, we get (x-2)(x-4). Now, since we want to find the zeroes, we have to make y equal to zero, or (x-2)(x-4) = 0. Using the zero-product property, we can conclude that if (x-2)(x-4) is 0, x is 2, 4. 
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The zeroes of the function x² - 6x +8 obtained using factorization are 4 and 2

Given the function :

  • f(x) = x² - 6x + 8

Using factorization :

x² - 6x + 8 = 0

x² - 4x - 2x + 8 = 0

x(x - 4) +2(x - 4) = 0

(x - 4)= 0 or (x - 2) = 0

Therefore, the values of X = 4 or 2

Therefore, the zeroes of the function are 4 and 2

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