Respuesta :
[tex] (-5xy^2) \times(-4x^2y)[/tex]
[tex]= (-5 \times -4) x^{1+2}y^{2+1}[/tex]
[tex]= 20 x^3 y^3[/tex]
Coefficient 20, exponent of x is 3, exponent of y is 3
[tex]= (-5 \times -4) x^{1+2}y^{2+1}[/tex]
[tex]= 20 x^3 y^3[/tex]
Coefficient 20, exponent of x is 3, exponent of y is 3
Answer: The required product is [tex]20x^3y^3.[/tex] Also, the coefficient of the product is 20, the exponent of x is 3 and the exponent of y is 3.
Step-by-step explanation: We are given to find the following product :
[tex]P=(-5xy^2)\times(-4x^2y).[/tex]
We will be using the following property of exponents :
[tex]x^a\times x^b=x^{a+b}.[/tex]
So, the multiplication is as follows :
[tex]P\\\\=(-5xy^2)\times(-4x^2y)\\\\=(-5)\times(-4)x^{1+2}y^{2+1}\\\\=20x^3y^3.[/tex]
Thus, the required product is [tex]20x^3y^3.[/tex] Also, the coefficient of the product is 20, the exponent of x is 3 and the exponent of y is 3.