PLEASE HELP FAST!! WILL GIVE BRAINLIEST!!
For the acids, use the formula pH = -log[H+]. (Because HCl has 1 H+ ion per formula unit, [H+] equals the molarity.) For water, us what you know about the pH of neutral solutions. For the bases, examine and extend the pattern.

PLEASE HELP FAST WILL GIVE BRAINLIEST For the acids use the formula pH logH Because HCl has 1 H ion per formula unit H equals the molarity For water us what you class=

Respuesta :

0.1M HCl              [H⁺]=0.1=10⁻¹       pH= - log 10⁻¹ = 1,  pH = 1
0.001M HCl          [H⁺]=0.001=10⁻³       pH= - log 10⁻³ = 3,  pH = 3
0.00001M HCl      [H⁺]=0.00001=10⁻⁵       pH= - log 10⁻⁵ = 5,  pH = 5
Distilled water                                           pH=7


0.00001 NaOH   [OH⁻]=10⁻⁵, [OH⁻][H⁺]=10⁻¹⁴, [H⁺]=10⁻¹⁴/10⁻⁵=10⁻⁹,
                           pH=9

0.001 NaOH   [OH⁻]=10⁻³, [OH⁻][H⁺]=10⁻¹⁴, [H⁺]=10⁻¹⁴/10⁻³=10⁻¹¹,
                           pH=11

0.1 NaOH   [OH⁻]=10⁻¹, [OH⁻][H⁺]=10⁻¹⁴, [H⁺]=10⁻¹⁴/10⁻¹=10⁻¹³,
                           pH=13

The pH of a solution shows how acidic or basic the solution is.

We are required to obtain the pH of solutions listed, from left to right, we have;

1) pH = -log(0.1 M) = 1

2) pH = - log(0.001 M) = 3

3) pH = -log (0.00001 M) = 5

4) Distilled water is neutral hence it has a pH of 7

5) pOH = -log(0.00001 M) = 5

pH = 14 - 5 = 9

6) pOH  = - log(0.001 M) = 3

pH = 14 - 3 = 11

7) pOH = - log(0.1 M) = 1

pH = 14 -1 = 13

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