Respuesta :
check the picture below.
since the y-axis is a North-South line, the perpendicular to that will be an East-West line, as you see in the picture.
hmmm what's its slope anyway, well, let's pick two points to get it, hmmm we have -4, -2, and let's see from the graph -1,-2 will do.
[tex]\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{-2}) \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-2-(-2)}{-1-(-4)} \\\\\\ \cfrac{-2+2}{-1+4}\implies \cfrac{0}{3}\implies 0[/tex]
since the y-axis is a North-South line, the perpendicular to that will be an East-West line, as you see in the picture.
hmmm what's its slope anyway, well, let's pick two points to get it, hmmm we have -4, -2, and let's see from the graph -1,-2 will do.
[tex]\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{-2}) \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-2-(-2)}{-1-(-4)} \\\\\\ \cfrac{-2+2}{-1+4}\implies \cfrac{0}{3}\implies 0[/tex]
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Answer:
The line perpendicular to the y-axis through the point (-4, -2) is y= -2
The slope of the line is 0
Step-by-step explanation: