For this case we can model the problem as a rectangle triangle.
We have:
Length of the sides of the triangle.
We want to find:
Length of the hypotenuse.
Using the Pythagorean theorem we have:
[tex]d ^ 2 = 2 ^ 2 + 2 ^ 2
[/tex]
[tex]d = \sqrt{2 ^ 2 + 2 ^ 2}
d = \sqrt{4 + 4}
d = \sqrt{8}
d = 2\sqrt{2}
[/tex]
Answer:
She is:
[tex]d = 2\sqrt{2} [/tex]
miles far from her starting point
