Respuesta :
For this case suppose that we have a quadratic equation of the form:
[tex]ax ^ 2 + bx + c [/tex]
The solution to the quadratic recuacion is given by:
[tex]x = \frac{-b +/- \sqrt{b^2 - 4ac}}{2a} [/tex]
Where,
The discriminant is:
[tex]b ^ 2 - 4ac [/tex]
When the discriminant is greater than zero, then the root is positive, and therefore, we have two positive real solutions.
Answer:
B. it has two real solutions
[tex]ax ^ 2 + bx + c [/tex]
The solution to the quadratic recuacion is given by:
[tex]x = \frac{-b +/- \sqrt{b^2 - 4ac}}{2a} [/tex]
Where,
The discriminant is:
[tex]b ^ 2 - 4ac [/tex]
When the discriminant is greater than zero, then the root is positive, and therefore, we have two positive real solutions.
Answer:
B. it has two real solutions