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Alain throws a stone off a bridge into a river below. The stone's height (in meters above the water), xxx seconds after Alain threw it, is modeled by: h(x)=-5x^2+10x+15h(x)=−5x 2 +10x+15h, left parenthesis, x, right parenthesis, equals, minus, 5, x, start superscript, 2, end superscript, plus, 10, x, plus, 15 What is the height of the stone at the time it is thrown?

Respuesta :

carlosego
For this case we have the following function:
 [tex]h (x) = - 5x ^ 2 + 10x + 15 [/tex]
 By the time the stone is thrown, x = 0.
 We must evaluate this value of x in the function.
 We have then:
 [tex]h (0) = - 5 (0) ^ 2 + 10 (0) +15 h (0) = 0 + 0 + 15 h (0) = 15 meters[/tex]
 Answer:
 The height of the stone at the time is thrown is given by:
 h (0) = 15 meters

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