For this case we have the following function:
[tex]y= \sqrt{10x+1}
[/tex]
We must have in mind that since the function is a square root, then the function is continuous for values greater than zero.
We have then:
[tex] 10x + 1 \geq 0
[/tex]
Clearing x we have:
[tex] 10x \geq -1
x \geq -1/10[/tex]
Therefore, the interval for which the function is:
[-1/10, inf)
Answer:
[-1/10, inf)
