Respuesta :
This sort of problem is solved easily by a graphing calculator.
a) The ball reaches its maximum height in 1.13 seconds.
b) The ball's maximum height is 30.25 feet.
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Since you want to know when and where the peak value of the function occurs, it is convenient to put it into vertex form.
h = -16(t² -(9/4)t) + 10
h = -16(t² -(9/4)t +(9/8)²) +10 +16(9/8)²
h = -16(t -9/8)² + 10 + 81/4
h = -16(t -9/8)² + 30 1/4
The vertex of the function is (9/8, 30 1/4) ≈ (1.13, 30.25).
a) The ball reaches its maximum height in 1.13 seconds.
b) The ball's maximum height is 30.25 feet.
_____
Since you want to know when and where the peak value of the function occurs, it is convenient to put it into vertex form.
h = -16(t² -(9/4)t) + 10
h = -16(t² -(9/4)t +(9/8)²) +10 +16(9/8)²
h = -16(t -9/8)² + 10 + 81/4
h = -16(t -9/8)² + 30 1/4
The vertex of the function is (9/8, 30 1/4) ≈ (1.13, 30.25).
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Answer:
The ball reaches its maximum height in 1.13 seconds.
b) The ball's maximum height is 30.25 feet.
Step-by-step explanation:
I had the same question and got it right