Answer:
[tex]3x^4+13x^3-3x^2+18x+4[/tex]
Step-by-step explanation:
Given: Using vertical multiplication method
[tex](x^2+5x+1)\times (3x^2-2x+4)[/tex]
For vertical multiplication, we write two expression one top and one bottom.
Now, we multiply last term of bottom expression with each term of first expression.
[tex]x^2+5x+1[/tex]
[tex]3x^2-2x+4[/tex]
[tex]4x^2+20x+4[/tex]
[tex]-2x^3-10x^2-2x+0[/tex]
[tex]3x^4+15x^3+3x^2+0+0[/tex]
[tex]3x^4+13x^3-3x^2+18x+4[/tex]
Hence, The product of [tex](x^2+5x+1)\times (3x^2-2x+4)[/tex] is [tex]3x^4+13x^3-3x^2+18x+4[/tex]
