The balanced reaction between aqueous nitric acid and aqueous strontium hydroxide is ________.
a.hno3(aq) + sr(oh)2(aq) → sr(no3)2 (aq) + h2 (g)
b.hno3(aq) + sr(oh)2 (aq) → h2o (l) + sr(no3)2 (aq)
c.hno3 (aq) + sroh (aq) → h2o (l) + srno3(aq)
d.2hno3 (aq) + sr(oh)2 (aq) → 2h2o (l) + sr(no3)2(aq)

The balanced reaction between aqueous nitric acid and aqueous strontium hydroxide is: 2 HNO₃(aq) + Sr(OH)₂ → 2 H₂O(l) + Sr(NO₃)₂(aq) (Option d)

Let's consider the unbalanced reaction between aqueous nitric acid and aqueous strontium hydroxide. This is a neutralization reaction and the products are strontium nitrate and water.

HNO₃(aq) + Sr(OH)₂ → H₂O(l) + Sr(NO₃)₂(aq)

We will balance it using the trial and error method.

First, we will balance N atoms by multiplying HNO₃ by 2.

2 HNO₃(aq) + Sr(OH)₂ → H₂O(l) + Sr(NO₃)₂(aq)

Finally, we get the balanced equation by multiplying H₂O by 2.

2 HNO₃(aq) + Sr(OH)₂ → 2 H₂O(l) + Sr(NO₃)₂(aq)

The balanced reaction between aqueous nitric acid and aqueous strontium hydroxide is: 2 HNO₃(aq) + Sr(OH)₂ → 2 H₂O(l) + Sr(NO₃)₂(aq) (Option d)

You can learn more about balancing equations here: https://brainly.com/question/7181548